Question

$x ^{2} + x = 20 \\ then \: find \: x \: value$
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Answer 1

hey mate this is ur solution

❤️

Answer 2

Step-by-step explanation:

${x }^{2} + x - 20 = 0 \\ {x}^{2} + 5x - 4x - 20 = 0 \\ x(x + 5) - 4(x + 5) = 0 \\ (x - 4)(x + 5) = 0 \\ x = 4 \: and \: - 5$

hope it helps u

mark as brainleast I