Math, asked by sureshk87317, 14 hours ago


x ^{2}  + x ^{3}  - 2x^{2}  + x + 1 \div x - 1
long bivison method ​

Answers

Answered by yogeeshwarantn1971
4

Answer:

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Step-by-step explanation:

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Answered by s1274himendu3564
4

x = 2-1/x

x = (2x-1)/x

x²-2x+1=0

x²-x-x+1=0

x(x-1)-1(x-1)=0

(x-1)(x-1)=0

x-1=0 or x-1=0

x= 1 or X= 1

Therefore value of x = 1

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