Question

$(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0$
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Answer 1

Answer:

$(x + 2)(x + 3) + ( x - 3)(x - 2) - 2x(x + 1) = 0$

$(x {}^{2} + 3x + 2x + 6) + (x {}^{2} - 2x - 3x + 6) - 2x(x + 1) = 0 \\ 2x {}^{2} + 12 - 2x {}^{2} - 2x = 0 \\ 12 - 2x = 0 \\ - 2x = - 12 \\ 2x = 12 \\ x = \frac{12}{2} \\ x = 6$

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