Question

$x^{2} (x^{4} -9)=8x^{4},$ if $x$ is positive, for what real value of $x$, is the equation above true?

Answer 1

Step-by-step explanation:

$x^{2} (x^{4} -9)=8x^{4},$

x⁴-9=8x²

x²=0, x=0

x⁴-8x²=9

x⁴-8x²+4² =9 + 4²

(x²-4)²=25

x²-4=5

x²=1

x=1