Question

$x^{2} +x=4$

Answer 1

Answer:

x² + x = 4

x² + x - 4 = 0

so.

a = 1

b= 1

c= -4

by formula,

- b +-√ b - 4ac /2a

do

Answer 2

Given:-

๛p(x)=x²+x-4

$\rule{200}{1}$

To Find:-

✪The Value of x?

$\rule{200}{1}$

AnsWer:-

➜x²+x-4=0

[•]a=1

(•)b=1

{•}c=-4

✪Using Discriminant Formula★

↝d=b²-4ac

↝d=(1)²-4×1×-4

↝d=1+16

↝d=17

➜√d=±√17

✪If Taking x(+)=$\frac{-b + \sqrt{d}}{2a}$

•x(+)=$\frac{-1+ \sqrt{17}}{2}$

★If Taking x(-)=$\frac{-b - \sqrt{d}}{2a}$

•x(-)=$\frac{-1- \sqrt{17}}{2}$

$\rule{200}{2}$