Math, asked by ASAnushSinha10, 7 months ago


x {}^{2}  - y {}^{2}  - 1 + y {}^{2}  - 1 - x {}^{2}  + 1 - x {}^{2}  - y {}^{2}  =

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Answered by jhak00746
0

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Answered by Anonymous
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x²-y²-1+y²-1-x²+1-x²-y² = ?

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The value of x²-y²-1+y²-1-x²+1-x²-y².

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x²-y²-1+y²-1-x²+1-x²-y²

First, we have to group all x², y² and 1 in three different groups.

∴ x²-y²-1+y²-1-x²+1-x²-y²

= (x²-x²-x²)+(-y²+y²-y²)+(-1-1+1)

In each group, we can see that there are two negative numbers and one positive number. So, one positive number and one negative number cancels out from each group.

∴ (x²-x²-x²)+(-y²+y²-y²)+(-1-1+1)

= (-x²)+(-y²)+(-1)

We can remove brackets.

∴ (-x²)+(-y²)+(-1)

= -x²-y²-1

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x²-y²-1+y²-1-x²+1-x²-y² = -x²-y²-1

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The value of (x²-y²-1+y²-1-x²+1-x²-y²) is (-x²-y²-1).

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