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x²-y²-1+y²-1-x²+1-x²-y² = ?
The value of x²-y²-1+y²-1-x²+1-x²-y².
x²-y²-1+y²-1-x²+1-x²-y²
First, we have to group all x², y² and 1 in three different groups.
∴ x²-y²-1+y²-1-x²+1-x²-y²
= (x²-x²-x²)+(-y²+y²-y²)+(-1-1+1)
In each group, we can see that there are two negative numbers and one positive number. So, one positive number and one negative number cancels out from each group.
∴ (x²-x²-x²)+(-y²+y²-y²)+(-1-1+1)
= (-x²)+(-y²)+(-1)
We can remove brackets.
∴ (-x²)+(-y²)+(-1)
= -x²-y²-1
x²-y²-1+y²-1-x²+1-x²-y² = -x²-y²-1
The value of (x²-y²-1+y²-1-x²+1-x²-y²) is (-x²-y²-1).
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