Question

$x(2x + 3) = 35 \: factorisation \: method$

Answer 1

$x(2x + 3) = 35 \\ \\ 2{x}^{2} + 3x = 35 \\ 2 {x}^{2} + 3x - 35 = 0 \\ 2 {x}^{2} + 10x - 7x - 35 = 0 \\ 2x(x + 5) - 7(x + 5) = 0 \\ (2x - 7)(x + 5) = 0 \\ \\ 2x - 7 = 0 \\ x = \frac{7}{3} \\ \\ x + 5 = 0 \\ x = - 5$