Question

$(x + 2y + 4 {)}^{2}$
​

Answer 1

We know that,

• $( a + b+ c )^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$

Now,

• $x^2 + 4y^2 + 16 + 2 × x × 2y + 2 × 2y × 4 + 2 × 4 × x$
• $x^2 + 4y^2 + 16 + 4xy + 16y + 8x$

hope it will helps you ✌️