Math, asked by pujakumari04389, 7 months ago


 ({x}^{3}  + 1) by (x + 1)

Answers

Answered by oOfRiEnDsHiPoO
1

Answer:

 \frac{  {x}^{3}  + 1 }{x + 1}  \\  \\  =  \frac{ {x}^{3}  +  {(1})^{3} }{x + 1}  \\  \\  =  \frac{(x + 1)( {x}^{2} - x + 1) }{x + 1}  \\  \\  =  {x}^{2}  - x + 1 \\  \\ (x + 1) \: and \: (x + 1) \: gets \: cancelled \\  \\ formula \: used \\  \\  {a}^{3}  +  {b}^{3}  \\  \\  = (a + b)( {a}^{2}  - ab +  {b}^{2} )

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Answered by Anonymous
0

Answer:

125677+77890+68

=677+788(-67)/908

=7(78998)

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