Question

${x}^{3} + 1 \div {x}^{3 } - 2$
plz help me to factorize...​

Answer 1

Hi buddy

Here is your answer

X3+1/x3-2

My answer is written assuming question is x^3 + (1/x)^3 - 2. Feel free to correct me if I am wrong.

To factorize x^3 + 1/x^3 - 2, take LCM of the expression.

Expression becomes, (x^6 - 2 x^3 + 1) / x^3. Now numerator is easily factorisable as (x^3 - 1)^2

So final expression is (x^3 - 1)^2 / x^3

x^3 - 1 = (x - 1)*(x^2 + x + 1)

So (x^3 - 1)^2 / x^3 = [(x - 1)^2 * (x^2 + x + 1)^2] / x^3