Question

$(x/3+1 ), (y-2/3)=(5/3,1/3)$ find x and y

Answer 1

Answer- The above question is from the chapter 'Linear Equations in Two Variables'.

Given question:  Find x and y:-

(x/3 + 1) , (y -2/3) = (5/3 , 1/3)

Solution: We have, (x/3 + 1) , (y -2/3) = (5/3 , 1/3) .

On comparison,

$\dfrac{x}{3} \: + \: 1 = \dfrac{5}{3}$

Transposing 1 to R.H.S., we get,

$\dfrac{x}{3} = \dfrac{5}{3} - 1$

$\dfrac{x}{3} = \dfrac{5 \: - \: 3}{3}$

$\dfrac{x}{3} = \dfrac{2}{3}$

⇒ x = 2

Similarly, on comparison,

$y \: - \:  \dfrac{2}{3} = \dfrac{1}{3}$

Transposing 2/3 to R.H.S., we get,

$y = \dfrac{1 \: + \: 2}{3}$

$y = \dfrac{3}{3}$

⇒ y = 1

∴ x = 2

∴ y = 1