![({x + 3)}^{2} + 5(x + 3) ({x + 3)}^{2} + 5(x + 3)](https://tex.z-dn.net/?f=+%28%7Bx+%2B+3%29%7D%5E%7B2%7D++%2B+5%28x+%2B+3%29)
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Answer:
(x + 3)² + 5(x + 3)= x²+6x+9 + 5x+15
= x² + 11x + 24
If x² + 11x + 24=0
Then x² + 3x + 8x + 24=0
or x(x+3) + 8(x+3)=0
or (x+3) (x+8)=0
or x=-3 or x=-8
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