Math, asked by creativeplayer27, 11 months ago


 {x}^{3}  - 2 {x}^{2}  - x + 2

Answers

Answered by Anonymous
0

Answer:

x {}^{3}  - 2x {}^{2}  - x + 2 \\ (x {}^{3}  - 2x {}^{2} ) - (x  +  2) = 0 \\x {}^{2} (x - 2) - 1(x - 2) = 0 \\ (x - 2)(x {}^{2}  - 1) = 0 \\ x - 2 = 0 \: or \: x {}^{2}  - 1 = 0 \\ x = 2 \: or \: x {}^{2} = 1 \\ x = 2 \: or \: x =  \sqrt{1}

Answered by raushankumar3604
0

Answer:

 {x}^{3}  - 2 {x}^{2}  - x  + 2 \\  {x}^{2} (x - 2) - 1(x  -  2) \\ ( {x}^{2}  - 1)(x - 2)

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