In partial fractions
Answers
Answer:
Find ∫ dx / [(x + 1) (x + 2)]
Answer : The integrand is a proper rational function. Therefore, by using the form of partial fraction from the image above, we have:
1 / [(x + 1) (x + 2)] = A / (x + 1) + B / (x + 2) … (1)
Solving this equation, we get,
A (x + 2) + B (x + 1) = 1
Or, Ax + 2A + Bx + B = 1
x (A + B) + (2A + B) = 1
For LHS to be equal to RHS, we have
A + B = 0 and 2A + B = 1. On solving these two equations, we get
A = 1 and B = – 1.
Therefore, we have
1 / [(x + 1) (x + 2)] = 1 / (x + 1) – 1 / (x + 2)
Hence, ∫ dx / [(x + 1) (x + 2)] = ∫ dx / (x + 1) – ∫ dx / (x + 2)
= log |x + 1| – log |x + 2| + C
Note: Equation (1) is true for all permissible values of x. Some authors use the symbol ‘≡’ to indicate that the statement is an identity and use the symbol ‘=’ to indicate that the statement is an equation, i.e., to indicate that the statement is true only for certain values of x.
Answer:
Refer to the attachment
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