Question

$x {}^{3} - 2x {}^{2} - x + 2 \div x + 1$
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Answer 1

$\frac{ {x}^{3} - 2 {x}^{2} - x + 2 }{x + 1} \\ = > \frac{ {x}^{3} + {x}^{2} - 3 {x}^{2} - 3x + 2x + 2 }{x + 1} \\ = > \frac{ {x}^{2} (x + 1) - 3x(x + 1) + 2(x + 1}{x + 1} \\ = > {x}^{2} - 3x + 2$