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Answer: The equation can be factorized as: x3 – 3x2 – 9x – 5 = (x+1)2 (x+5) We will find one of the zeros of the expression x3 – 3x2 – 9x – 5 and use long division to find the other zeros.
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Solution :-
➜ x³ - 3x² - 9x - 5
➞ x³ + x² - 4x² - 4x - 5x - 5
➞ x²(x + 1) - 4x(x + 1) - 5(x + 1)
➞ (x + 1) (x² - 4x - 5)
➞ (x + 1) {x² - (5 - 1)x - 5}
➞ (x + 1) {x² - 5x + x - 5}
➞ (x + 1) {x(x - 5) + 1(x - 5)}
➞ (x + 1) (x - 5) (x + 1)
∴ The answer of this question is (x + 1) (x - 5) (x + 1)
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