Math, asked by daljeet17kaur19, 3 months ago


x =  - 3 \sqrt{2}
x^2+kx-6=0​

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Answered by sivakumar0930
0

Answer:

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Step-by-step explanation:

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Answered by vidyabharathi23
1

Step-by-step explanation:

x = -  3 \sqrt{2}

 {x}^{2}  + kx - 6 = 0 \\ substitute \: x \: value \: in \: the \: equation \: then \\  ( { - 3 \sqrt{2} })^{2}  +  (- 3 \sqrt{2} )k - 6 = 0 \\( 9 \times 2 )- 3 \sqrt{2} k - 6 = 0 \\ 3 \sqrt{2} k = 12 \\ k =  \frac{12}{3 \sqrt{2} }  \\ multiply \sqrt{2} numerator \: and \: denominator \: then \\ k = 2 \sqrt{2}

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