Question

$x = - 3 \sqrt{2}$
x^2+kx-6=0​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$x = - 3 \sqrt{2}$

${x}^{2} + kx - 6 = 0 \\ substitute \: x \: value \: in \: the \: equation \: then \\ ( { - 3 \sqrt{2} })^{2} + (- 3 \sqrt{2} )k - 6 = 0 \\( 9 \times 2 )- 3 \sqrt{2} k - 6 = 0 \\ 3 \sqrt{2} k = 12 \\ k = \frac{12}{3 \sqrt{2} } \\ multiply \sqrt{2} numerator \: and \: denominator \: then \\ k = 2 \sqrt{2}$