Math, asked by jadhavsantosh52717, 4 months ago


 {x} ^3 -   {x}^2 - (3 -  \sqrt{3} )x +  \sqrt{3}
is this polynomial has (x+1) as a factor ​

Answers

Answered by lalitnit
0

Answer:

 {x}^{3}  -  {x}^{2}  - (3 -  \sqrt{3} )x +  \sqrt{3}  \\  =  - 1 - 1 + 3 -  \sqrt{3} +  \sqrt{3}   \\ 1

No (x+1) is not a factor of the polynomial.

Answered by tennetiraj86
1

Step-by-step explanation:

Given polynomial is p(x)=-x²-(3-3)x+3

given another polynomial is (x+1)

we know that by factor theorem

a polynomial (x+a) is a factor of p(x) if p(x)=0

=>If (x+1) is a factor then p(-1)=0

=>p(-1)=(-1)³-(-1)²-(3-3)(-1)+3

=>-1-1+3-3+3

=>-2+3+0

=>1

p(-1)=1

So (x+1) is not a factor of x³-x²-(3-√3)x+√3

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