is this polynomial has (x+1) as a factor
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0
Answer:
No (x+1) is not a factor of the polynomial.
Answered by
1
Step-by-step explanation:
Given polynomial is p(x)=x³-x²-(3-√3)x+√3
given another polynomial is (x+1)
we know that by factor theorem
a polynomial (x+a) is a factor of p(x) if p(x)=0
=>If (x+1) is a factor then p(-1)=0
=>p(-1)=(-1)³-(-1)²-(3-√3)(-1)+√3
=>-1-1+3-√3+√3
=>-2+3+0
=>1
p(-1)=1
So (x+1) is not a factor of x³-x²-(3-√3)x+√3
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