Answers
Answered by
5
Answer :
Now, x³ + y - xy - x
= (x³ - x) - (xy - y)
= x (x² - 1) - y (x - 1)
= x (x - 1) (x + 1) - y (x - 1)
= (x - 1) (x² + x - y),
which is the required factorization.
#MarkAsBrainliest
Now, x³ + y - xy - x
= (x³ - x) - (xy - y)
= x (x² - 1) - y (x - 1)
= x (x - 1) (x + 1) - y (x - 1)
= (x - 1) (x² + x - y),
which is the required factorization.
#MarkAsBrainliest
Answered by
5
x³ + y - xy - x
x³ - x - xy + y
x(x² - 1²) - y(x - 1)
x(x - 1)(x + 1) - y(x - 1)
(x - 1)[ x(x + 1) - y]
(x - 1)(x² + x - y)
I hope this will help you
(-:
x³ - x - xy + y
x(x² - 1²) - y(x - 1)
x(x - 1)(x + 1) - y(x - 1)
(x - 1)[ x(x + 1) - y]
(x - 1)(x² + x - y)
I hope this will help you
(-:
Similar questions