Question

$x(3x-1)=2$
solve the following equation

Answer 1

Answer:

✧ x = 1

✧ x = - 2/3

Step-by-step explanation:

➛ x( 3x - 1 ) = 2

First multiply x with both the terms i.e, with 3x and - 1 respectively. x × 3x = 3x² and - 1 × x = - x.

➛ ( 3x × x ) ( - 1 × x ) = 2

➛ 3x² - x = 2

Now substract 2 from both the sides, we have:

➛ 3x² - x - 2 = 2 - 2

➛ 3x² - x - 2 = 0

Now, factorise it.

When a trinomial is in the form ax² + bx + c, split b i.e, the coefficient of x in the middle term into two parts such that the sum of these two parts is equal to b and the product of these two parts is equal to product of a and c.

➛ 3x² - 3x + 2x - 2 = 0

➛ 3x² - 3x + 2x - 2 = 0

➛ 3x ( x - 1 ) +2 ( x - 1 ) = 0

➛ ( x - 1 ) ( 3x + 2 ) = 0

Take,

➛ ( x - 1 ) = 0

➛ x - 1 = 0

➛ x = 1

Then, take

➛ ( 3x + 2 ) = 0

➛ 3x + 2 = 0

➛ 3x = - 2

➛ x = - 2/3

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