![x(3x + 2) = 3x + 2 x(3x + 2) = 3x + 2](https://tex.z-dn.net/?f=x%283x+%2B+2%29+%3D+3x++%2B+2)
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x(3x+2) = (3x+2)
x(3x+2) -1(3x+2) = 0
(3x+2)(x-1) = 0
3x+2 = 0 or x-1 = 0
Therefore, x=
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