Question

$x^{4}+17x^{2} +23=0$
Find x

Answer 1

Answer:

PUT X² = t

NEW EQUATION -

${t}^{2} + 17t + 23 = 0$

SOLUTION OF EQUATION -

$t = \frac{ - 17 + \binom{ + }{ - } \sqrt{ {(17)}^{2} - 4 \times 23} }{2}$

$t = \frac{ - 17 + \binom{ + }{ - } \sqrt{197} }{2}$

$t = \frac{ - 17 + \sqrt{197} }{2} \: \: and \: \: t = \frac{ - 17 - \sqrt{197} }{2}$

SO ,

$x = \sqrt{ \frac{ - 17 + \sqrt{197} }{2} } \: \: and \: \: x = \sqrt{ \frac{ - 17 - \sqrt{197} }{2} }$

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Answer 2

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