Question

$(x - 4) {}^{2} + 5^{2} = 13 {}^{2}$
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Answer 1

Step-by-step explanation:

$\implies$ $(x-4)^{2} + 5^{2}=13^{2}$

$\implies$ $x^{2}+4^{2}-2(x)(4)+25=169$

$\implies$ $x^{2}+16-8x+25=169$

$\implies$ $x^{2}-8x-128=0$

$\implies$ $x^{2}-16x+8x-128=0$

$\implies$ $x(x-16)+8(x-16)=0$

$\implies$ $(x+8)(x-16)=0$

$\implies$ $\large\boxed{x=-8\:or\:x=16}$

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