Question

${x}^{4} -7 {x}^{2} + 12$
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Answer 1

x⁴-7x²+12

= x⁴-4x²-3x²+12

= x²(x²-4)-3(x²-4)

= (x²-4)(x²-3)

= (x²-2²)(x²-3)

= (x+2)(x-2)(x²-3) Ans.

I hope this helps.

Answer 2

Answer:

$({x}^{2} - 3)(x + 2)(x - 2)$

Step-by-step explanation:

${x}^{4} - 7 {x}^{2} + 12 \\ = > {x}^{4} - 4 {x}^{2} - 3 {x}^{2} + 12 \\ = > {x}^{2} ( {x}^{2} - 4) - 3( {x}^{2} - 4) \\ = > ({x}^{2} - 3)( {x}^{2} - 4) \\ = > ( {x}^{2} - 3)(x + 2)(x - 2)$