Question

${x}^{4} + {y}^{4} = 82$
$x - y = 2$
find for x and y.​

pls solve it

Answer 1

Answer:

Step-by-step explanation:

x - y = 2

x = 2 + y                                                                   [1]

x^4 + y^4 = 82

(x^2)^2 + (y^2)^2=82

(x^2 + y^2)^2 = 82

x^2 + y^2 =  $\sqrt{82}$

(2 + y) ^2 + y^2 =  $\sqrt{82}$

4 +  y^2 + 4y + y^2 =  $\sqrt{82}$

2 y^2  + 4y + 4 -  $\sqrt{82}$ = 0

sove by middle term splitting

you will get value of y

then put the value of y in equation 1

you will get value of x