Question

$x + 5 \6 - x + 1 \div 9 = x + 3 \div 4$
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Answer 1

Answer:

$x + \frac{5}{6} - x + 1 \div 9 = x + 3 \div 4$

If this is your question ↑

$x - x + \frac{5}{6} + 1 \div 9 = x + 3 \div 4 \\ \frac{5}{6} + 1 \div 9 = x + 3 \div 4 \\ \frac{5}{6} + \frac{1}{1} \div 9 = x + 3 \div 4 \\ \frac{11}{6} \div 9 = x + 3 \div 4 \\ \frac{11}{6} \times \frac{1}{9} (reciprocal) = x + 3 \div 4 \\ \frac{11}{54} = x + 3 \div 4 \\ \frac{11}{54} \times \frac{4}{1} = x + 3 \\ after \: cancellation \\ \frac{11}{27} - 3 = x \\ \frac{11}{27} - \frac{81}{27} = x \\ \frac{ - 70}{27} = x$

Answer 2

Answer:

$Answer:</p><p></p><p>x + \frac{5}{6} - x + 1 \div 9 = x + 3 \div 4x+65−x+1÷9=x+3÷4</p><p></p><p>If this is your question ↑</p><p></p><p>\begin{gathered}x - x + \frac{5}{6} + 1 \div 9 = x + 3 \div 4 \\ \frac{5}{6} + 1 \div 9 = x + 3 \div 4 \\ \frac{5}{6} + \frac{1}{1} \div 9 = x + 3 \div 4 \\ \frac{11}{6} \div 9 = x + 3 \div 4 \\ \frac{11}{6} \times \frac{1}{9} (reciprocal) = x + 3 \div 4 \\ \frac{11}{54} = x + 3 \div 4 \\ \frac{11}{54} \times \frac{4}{1} = x + 3 \\ after \: cancellation \\ \frac{11}{27} - 3 = x \\ \frac{11}{27} - \frac{81}{27} = x \\ \frac{ - 70}{27} = x\end{gathered}x−x+65+1÷9=x+3÷465+1÷9=x+3÷465+11÷9=x+3÷4611÷9=x+3÷4611×91(reciprocal)=x+3÷45411=x+3÷45411×14=x+3aftercancellation2711−3=x2711−2781=x27−70=x</p><p></p><p>$