Question

$x + 7 \leqslant 11$
solve._.​

Answer 1

Answer:

=>

(x+2)(x+4)(x+7)

(x−2)(x−4)(x−7)

>1

=>

(x+2)(x+4)(x+7)

(x−2)(x−4)(x−7)−1

>0

=>

(x+2)(x+4)(x+7)

(x

2

−6x+8)(x−7)−(x

2

+6x+8)(x+7)

>0

=>

(x+2)(x+4)(x+7)

x

2

−7x

2

−6x

2

+42x+8x−56−x

2

−6x

2

−8x−7x

2

−42x−56

>0

=>

(x+2)(x+4)(x+7)

−26x

2

−112

>0

=>

(x+2)(x+4)(x+7)

26x

2

+112

<0

=>xϵ(−∞,−7)∪(−4,−2).

Answer 2

Answer:

x =4

Explanation:

4+7=11

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