Question

$x = 9 \: and \: y = \sqrt{17} \: then \: the \: value \: of \: ({x}^{2} - {y}^{2} ) { - }^{ \frac{1}{3} }$
Find out the value ​

Answer 1

Step-by-step explanation:

Given:- x=9. y=√17

find:- value of

$( {x}^{2} - {y}^{2} ) {}^{ - \frac{1 }{3} }$

solve:-

$( {9}^{2} - { \sqrt{17} }^{2} ) {}^{ - \frac{1}{3} } = (81 - 17) {}^{ - \frac{1}{3} }$

i.e.

${64}^{ - \frac{1}{3} }$

i.e.

$( {4}^{3} ) {}^{ - \frac{1}{3} } = \frac{1}{( {4}^{3}) {}^{ \frac{1}{3} } } = \frac{1}{4}$

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