Question

$(x-a)^2 - (x+a)^2 = 0 then the value of x is$

Answer 1

Answer:

$\\\tt x=0$

Step-by-step explanation:

Given:

$\\\tt (x-a)^2 - (x+a)^2=0$

Using

$\\\tt p^2 - q^2=(p+q)(p-q)$

We have,

$\\\tt \implies (x-a +x+a) (x-a-x-a)=0$

$\\\tt \implies 2x(-2a)=0$

$\\\tt \implies x=0$

Answer 2

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