Question

${ {x}^{(a + b)} {}^{2} \: \: \times {x}^{(b + c)} {}^{2} \: \times {x}^{(c + a)} {}^{2}} \div {{x}^{a} \times {x}^{b} \times {x}^{c} } whole \: power4$
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Answer 1

Answer:

hola mate

see the attachment

hope it helps u

Answer 2

⭐Solution⭐

✏ given here ✔

[ (x)^(a+b)² × (x)^(b+c)²×(x)^(c+a)²]/(x^a × x^b × x^c)⁴

= [ (x)^(2a+2b)×(x)^(2b+2c)×(x)^(2c+2a)]/[(x)^(4a) × (x)^(4b) × (x)^(4c)]

= (x)^(2a+2b+2b+2c+2c+2a)/(x)^(4a+4b+4c)

= (x)^(4a+4b+4c)/(x)^(4a+4b+4c)

= 1.

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✏Hopes its help's u.

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