Question

$( { {x}^{a - b} })^{a + b} \times { {x}^{(b - c)(b + c)} } { {x}^{(c - a)(c + a) = 1} }$
verify it pls answer me pls ​

Answer 1

Answer:

LHS,

${x}^{(a - b)(a + b)} {x}^{(b - c)(b + c)} {x}^{(c - a)(c + a)}$

$= {x}^{ ( {a}^{2} - {b}^{2} ) } {x}^{ ({b}^{2} - {c}^{2} ) } {x}^{( {c}^{2} - {a}^{2}) }$

$= {x}^{( {a}^{2} - {b}^{2} + {b}^{2} - {c}^{2} + {c}^{2} - {a}^{2} ) }$

$= {x}^{0}$

$= 1$

= RHS (Proved)

Step-by-step explanation:

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