Question

${(x + \frac{1}{a} )}^{2} - {b}^{2} = 0$
ANSWER WITH EXPLANATION!!!
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Answer 1

Answer:

(x+1/a)²-b²=0

x²+1/a²+2x/a-b²=0

x²+2x/a+1/a²-b²=0

D=0

D=b²-4ac

D=4/a²-4(1/a²-b²)

D=4b²

x= -b+ √D/2a ,x= -b-√D/2a

x= -b -1/a

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