Question

$x + \frac{1}{x} = 11 \: find \: the \: value \: of \: {x}^{2} + \frac{1}{ {x}^{2} }$
pls can you solve this in 5 min pls help me​

Answer 1

Step-by-step explanation:

$x + \frac{1}{x} = 11$

squaring on both hand side

$( {x}^{} + \frac{1}{ {x}^{} } ) {}^{2} = (11) {}^{2}$

${x}^{2} + \frac{1}{x} {}^{2} + 2 \times x \times \frac{1}{x} = 121 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 121 - 2 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 119$