Question

$x - \frac{1}{x} = 13 \: \: find \: \: {x}^{4} + \frac{1}{ {x}^{4} }$
Pls if anybody does it correctly I'll mark them as brainlist.​

Answer 1

Step-by-step explanation:

$x - \frac{1}{x} = 13 \\ (x - \frac{1}{x} )^{2} = 169 \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 169 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 171 \\ ( {x}^{2} + \frac{1}{ {x}^{2} } ) ^{2} = (171)^{2} \\ = {x}^{4} + \frac{1}{ {x}^{4} } + 2 = 29241 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 29239$

please mark my answer as brainliest ❤️❤️