Question

$x + \frac{1}{x} = 5 \\ then \: find \: the \: value \: of \\ {x}^{2} + \frac{1}{ {x}^{2} }$
find the value​

Answer 1

Answer:

${x}^{2} + ({ \frac{1}{x} })^{2} = 23$✔✔

Step-by-step explanation:

$x + \frac{1}{x} = 5 \: \: (given) \\ so \: we \: go \: through \: the \: formula \: of( {x + y})^{2} \\ bcz \: when \: we \: solve \: these \: types \: of \: maths \: we \: use \: these \: formula \\ we \: have \: t o \: find \\ {x}^{2} + \frac{1}{ {x}^{2} } \\ ( {x + \frac{1}{x} })^{2} = {x}^{2} + ( { \frac{1}{x} })^{2} + 2 \times x \times \frac{1}{x} \\ {5}^{2} = {x}^{2} + ({ \frac{1}{x} })^{2} + 2 \\ 25 - 2 = {x}^{2} + ({ \frac{1}{x} })^{2} \\{x}^{2} + ({ \frac{1}{x} })^{2} = 23$

Answer 2

This is the answer !! Hope it helps mate..!!