Question

$x - \frac{1}{x} = \frac{1}{3} \: evaluate \: {x}^{3} - \frac{1}{ {x}^{3} }$
Very urgent, please help​

Answer 1

Answer:

$= > \frac{28}{27} = 1 \frac{1}{27}$

Step-by-step explanation:

$x {}^{3} - \frac{1}{x} {}^{3} = (x - \frac{1}{x} ) {}^{3} + 3(x - \frac{1}{x} )$

$x {}^{3} - \frac{1}{x} {}^{3} = \frac{1}{3} {}^{3} + 3( \frac{1}{3} )$

$x {}^{3} - \frac{1}{x} {}^{3} = \frac{1}{27} + 1$

$x {}^{3} - \frac{1}{x} {}^{3} = \frac{1 + 27}{27}$

$x {}^{3} - \frac{1}{x} {}^{3} = \frac{28}{27}$