Math, asked by 15799, 2 months ago


(x + \frac{b}{3} )^{3}  - \frac{b^{2}x}{3a} - \frac{ {b}^{3}}{27a^{3}} +  \frac{cx}{a} +\frac{d}{a} = 0
Bring all the terms on RHS except X. Bring X on LHS and all the other terms on RHS( X should not be on RHS.).

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Answers

Answered by bkbebybahen
3

Answer:

Use grouping to factorise the numerator and take out the common factor \(ax\) in the denominator\[\frac{\left(ax - ab\right) + \left(x - b\right)}{a{x}^{2} - abx} = \frac{a\left(x - b\right) + \left(x - b\right)}{ax\left(x - b\right)}\]

Take out common factor \(\left(x-b\right)\) in the numerator\[=\frac{\left(x - b\right)\left(a + 1\right)}{ax\left(x - b\right)}\]

Cancel the common factor in the numerator and the denominator to give the final answer

=a+1ax

Step-by-step explanation:

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