Math, asked by devu1847, 11 months ago


x =   \frac{ \sqrt{a {}^{2}  +b {}^{2}  }  +  \sqrt{a {}^{2}  - b {}^{2} }  }{ \sqrt{a {}^{2}  + b {}^{2} }   -  \sqrt{a {}^{2}  - b {}^{2} }  }   \: then \: prove \: that \: b { }^{2}  = \frac{2a {}^{2} x}{x {}^{2} + 1 }

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Answered by mihirvk15
1

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