Math, asked by divya9554, 9 months ago


x^{m}   \div x^{n}   \times x  ^{n}  \div x ^{o}  \times x  ^{o}  \div x ^{m}

Answers

Answered by karan42561
1

Solution :

x^m ÷x^n × x^n÷x^0 × x^0 ÷x^m

= x^(m-n) × x(n-0)× x^(0-m)

= x^(m-n) × x^n × x^-m

= x^(m-n) × [x^(n-m)] ==> x^[(m-n) +(n-m)]

= x^(m-n+n-m) ====> x^0

= 1

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Answered by Rohit18Bhadauria
0

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