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Solution :
x^m ÷x^n × x^n÷x^0 × x^0 ÷x^m
= x^(m-n) × x(n-0)× x^(0-m)
= x^(m-n) × x^n × x^-m
= x^(m-n) × [x^(n-m)] ==> x^[(m-n) +(n-m)]
= x^(m-n+n-m) ====> x^0
= 1
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