Math, asked by jay654235, 1 month ago


x squre - 6 = 2 \sqrt{2x}
using quadratic formula

Answers

Answered by vipinkumar212003
0

Answer:

 {x}^{2}  - 6 = 2 \sqrt{2} x \\  {x}^{2} - 2 \sqrt{2} x - 6 = 0 \\  {x }^{2}  - 3 \sqrt{2} x +  \sqrt{2} x - 6 = 0 \\  x(x - 3 \sqrt{2} ) +  \sqrt{2} (x - 3 \sqrt{2} ) = 0 \\  (x +  \sqrt{2} )(x - 3 \sqrt{2}) = 0 \\ x =  -  \sqrt{2}, \:  \:  3 \sqrt{2}  \\  \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}

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