Question

$x(x + 4) = 12$
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Answer 1

$\huge\boxed{answer}$

$\: \: \: \: \: \: \: \: \: x(x + 4) = 12$

$= > {x}^{2} + 4x - 12 = 0$

$a = 1 \: and \: b = 4 \: and \: c = - 12$

$= > {x}^{2} + 6x - 2x - 12 = 0$

$= >x(x + 6) - 2(x + 6) = 0$

$= > (x + 6)(x - 2) = 0$

$= > x = - 6 \: or \: x = 2$

$\underline{hope \: it \: helps \: you}$