Question

$(x)(x) = 4$
$a.2x ^2 = 4$
$b.2x ^ 2 - 4 = 0$
$c.x ^2 - 4 = 0$
$d.x^2 + 4 = 0$

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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Roots of the quadratic equation ax

2

+bx+c=0 are non real.

⇒b

2

−4ac<0 -----(1)

Now, for the expression a

2

x

2

+abx+ac,

Δ=a

2

b

2

−4a

3

c=a

2

(b

2

−4ac)<0 from (1)

Since, discriminant value is less than zero, coefficient of x

2

and expression always have same sign.

∴a

2

x

2

+abx+ac>0

Hence, option A.