Question

$(x + y - 1) ^{3}$
solve

Answer 1

Hope u like my process
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Formula to be used
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(a - b) ³ = a³ - b³ - 3ab(a-b)

(a + b) ³ = a³ +b³ +3ab(a+b)
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${(x + y - 1)}^{3} \\ \\ = {((x + y) - 1)}^{3} \\ \\ = {(x + y)}^{3} - {1}^{3} - 3(x + y).1.(x + y - 1) \\ \\ = (x + y)( {(x + y)}^{2} - 3(x + y - 1)) - 1 \\ \\ = (x + y)( {(x + y)}^{2} - 3(x + y)) + 3(x + y) - 1 \\ \\ = (x + y) ^{2} (x + y - 3) + 3(x + y) - 1 \\ \\ = (x + y) ^{3} - 3 {(x + y)}^{2} + 3(x + y) - 1 \\ \\ = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2} - 3 {x}^{2} - 3 {y}^{2} - 6xy + 3x + 3y - 1$
Hope this is ur required answer

Proud to help you

Answer 2

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