Question

$x + y = 10 \\ x - y = 4$
Solve by substitution elimination and cross multiplication method
pleaseee need urgent ​

Answer 1

Answer:

The given system of equations is

2x + 3y + 8 = 0

4x + 5y + 14 = 0

By cross-multiplication, we get



⇒x3×14−5×8=x3×14−5×8=12×5−4×3

⇒x42−40=−y28−32=110−12

⇒x2=−y−4=1−2

⇒x2 = −12

⇒ x = – 1

⇒−y−4 = −12

⇒ y = – 2

Hence, the solution is x = – 1, y = – 2

We can verify the solution.