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Answer:
Given x+y=2 and
x
1
+
y
1
=2
Then
x
1
+
y
1
=2
⇒
xy
x+y
=2
⇒
xy
2
=2
⇒xy=1
We know that
X
3
+y
3
=(x+y)
3
−3xy(x+y)⇒x
3
+y
3
=(2)
3
−3(1)(2)=8−6=2
Step-by-step explanation:
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