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Example: solve √(2x−5) − √(x−1) = 1
isolate one of the square roots:√(2x−5) = 1 + √(x−1) square both sides:2x−5 = (1 + √(x−1))2 ...
expand right hand side:2x−5 = 1 + 2√(x−1) + (x−1) ...
isolate the square root:√(x−1) = (x−5)/2. ...
Expand right hand side:x−1 = (x2 − 10x + 25)/4. ...
Multiply by 4 to remove division:4x−4 = x2 − 10x + 25.
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Solving Radical
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Answer:
(x+y+3)²
=x²+y²+9+2xy+6y+6x[using (a+b+c)²=a²+b²+c²+2ab+2bc+2ca)]
Therefore the answer is x²+y²+9+2xy+6y+6x
Hope it is clear....
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