Math, asked by Telex22, 1 month ago


 {(x + y)}^{3}  + (x - y) {}^{3}  =  \\  \\ 1) \: 2 {x}^{2}  + 6x {y}^{2}  \\  2) {x}^{2}  +  {y}^{2}  - 6xy \\ 3)2 {y}^{2}  - 2 {x}^{2} y \\ 4)2 {x}^{2}   - 6x {y}^{2}

Answers

Answered by mahendra15aug
4

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Answered by Sahan677
32

2{x}^{3}+6x{y}^{2}

Step by Step

{(x + y)}^{3} + (x - y) {}^{3}

(x+y)({x}^{2}+2xy+{y}^{2})+{(x-y)}^{3}

x({x}^{2}+2xy+{y}^{2})+y({x}^{2}+2xy+{y}^{2})+{(x-y)}^{3}

{x}^{3}+2{x}^{2}y+x{y}^{2}+y({x}^{2}+2xy+{y}^{2})+{(x-y)}^{3}

{x}^{3}+2{x}^{2}y+x{y}^{2}+y{x}^{2}+2{y}^{2}x+{y}^{3}+{(x-y)}^{3}

{x}^{3}+2{x}^{2}y+x{y}^{2}+y{x}^{2}+2{y}^{2}x+{y}^{3}+(x-y)({x}^{2}-2xy+{y}^{2})

{x}^{3}+2{x}^{2}y+x{y}^{2}+y{x}^{2}+2{y}^{2}x+{y}^{3}+x({x}^{2}-2xy+{y}^{2})-y({x}^{2}-2xy+{y}^{2})

{x}^{3}+2{x}^{2}y+x{y}^{2}+y{x}^{2}+2{y}^{2}x+{y}^{3}+{x}^{3}-2{x}^{2}y+x{y}^{2}-y({x}^{2}-2xy+{y}^{2})

{x}^{3}+2{x}^{2}y+x{y}^{2}+y{x}^{2}+2{y}^{2}x+{y}^{3}+{x}^{3}-2{x}^{2}y+x{y}^{2}-(y{x}^{2}-2{y}^{2}x+{y}^{3})

{x}^{3}+2{x}^{2}y+x{y}^{2}+y{x}^{2}+2{y}^{2}x+{y}^{3}+{x}^{3}-2{x}^{2}y+x{y}^{2}-y{x}^{2}+2{y}^{2}x-{y}^{3}

2{x}^{3}+6x{y}^{2}

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