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( x + y ) ( 3x - 7 ) - ( x + y ) ( 2x - 11 )
Taking ( x + y ) as common, we get
= ( x + y ) [ ( 3x - 7 ) - ( 2x - 11 ) ]
= ( x + y ) [ 3x - 7 - 2x + 11 ]
= ( x + y ) ( x + 4 )
Taking ( x + y ) as common, we get
= ( x + y ) [ ( 3x - 7 ) - ( 2x - 11 ) ]
= ( x + y ) [ 3x - 7 - 2x + 11 ]
= ( x + y ) ( x + 4 )
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