Math, asked by kavitabhuria2, 4 months ago


(x + y + 4z) ^{2}

Answers

Answered by sehgalp381
14

Answer:

(x + y + 4z) {}^{2}  \\ x {}^{2}  + y {}^{2}  +( 4z) {}^{2}  + 2 \times x \times y \times 4z \\ x {}^{2}  + y {}^{2}  + 16z {}^{2}  + 8xyz

Step-by-step explanation:

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