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Hope this helps you
Step-by-step explanation:
Solve for xx:
2−x3x+1=22−x3x+1=2
Multiply both sides of the equation by (3x+1)(3x+1)
Division by 00 is undefined so there must be a restriction: (x≠−13)(x≠−13).
2−x3x+1(2−x)=2=2(3x+1)2−x3x+1=2(2−x)=2(3x+1)
Expand the brackets and simplify
2−x−x−6x−7x=6x+2=2−2=02−x=6x+2−x−6x=2−2−7x=0
Divide both sides by −7−7
xx=0−7=0x=0−7x=0
Check the answer by substituting the solution back into the original equation
LHS =2−(0)3(0)+1=2= RHSLHS =2−(0)3(0)+1=2= RHS
Since both sides are equal, the answer is correct.
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